For an object placed at a distance 2.4 m from a lens, a sharp focused image is observed on a screen placed at a distance 12 cm from the lens. A glass plate of refractive index 1.5 and thickness 1 cm is introduced between lens and screen such that the glass plate plane faces parallel to the screen. By what distance should the object be shifted so that a sharp focused image is observed again on the screen?
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Applying lens formula

Upon putting the glass slab, shift of image is

Now 
Again apply lens formula

Solving u = - 5.6m
Thus shift of object is 5.6 – 2.4 = 3.2m
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